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TEKST ZADATKA

Ako je f(x)=2x+5, f(x) = 2x + 5 , g(x)=5x+3, g(x) = 5x + 3 , odrediti ff, f \circ f , fg, f \circ g , gf g \circ f i gg. g \circ g .


REŠENJE ZADATKA

Računamo kompoziciju ff: f \circ f :

(ff)(x)=f(f(x))=f(2x+5)=2(2x+5)+5=4x+10+5=4x+15(f \circ f)(x) = f(f(x)) = f(2x + 5) = 2(2x + 5) + 5 = 4x + 10 + 5 = 4x + 15

Računamo kompoziciju fg: f \circ g :

(fg)(x)=f(g(x))=f(5x+3)=2(5x+3)+5=10x+6+5=10x+11(f \circ g)(x) = f(g(x)) = f(5x + 3) = 2(5x + 3) + 5 = 10x + 6 + 5 = 10x + 11

Računamo kompoziciju gf: g \circ f :

(gf)(x)=g(f(x))=g(2x+5)=5(2x+5)+3=10x+25+3=10x+28(g \circ f)(x) = g(f(x)) = g(2x + 5) = 5(2x + 5) + 3 = 10x + 25 + 3 = 10x + 28

Računamo kompoziciju gg: g \circ g :

(gg)(x)=g(g(x))=g(5x+3)=5(5x+3)+3=25x+15+3=25x+18(g \circ g)(x) = g(g(x)) = g(5x + 3) = 5(5x + 3) + 3 = 25x + 15 + 3 = 25x + 18